问题
解答题
(1+
|
答案
设
+1 2
+…1 3
=a,则:1 1999
(1+
+1 2
+…1 3
)×(1 1999
+1 2
+…+1 3
)-(1+1 2000
+1 2
+…+1 3
)×(1 2000
+1 2
+…1 3
)1 1999
=(1+a)(a+
)-(1+a+1 2000
)×a,1 2000
=a+
+a2+1 2000
-a-a2-a 2000
,a 2000
=
.1 2000