问题 解答题
用递等式计算.
(1)406+4480÷28         
(2)17
5
7
-1
8
9
-1
5
7

(3)
3
8
÷(
7
8
-
1
4
)×5.5
(4)
1
3
÷
5
4
+
2
3
×
4
5
             
(5)5-(
1
12
+
1
15
)×30
(6)[1
1
3
-(2.5-1
2
3
)]÷
1
8
答案

(1)406+4480÷28,

=406+160,

=566;

(2)17

5
7
-1
8
9
-1
5
7

=17

5
7
-1
5
7
-1
8
9

=16-1

8
9

=14

1
9

(3)

3
8
÷(
7
8
-
1
4
)×5.5,

=

3
8
÷
5
8
×5.5,

=

3
5
×5.5,

=3.3;

(4)

1
3
÷
5
4
+
2
3
×
4
5

=

1
3
×
4
5
+
2
3
×
4
5

=(

1
3
+
2
3
)×
4
5

=1×

4
5

=

4
5

(5)5-(

1
12
+
1
15
)×30,

=5-(

1
12
×30+
1
15
×30),

=5-(2.5+2),

=5-4.5,

=0.5;

(6)[1

1
3
-(2.5-1
2
3
)]÷
1
8

=[1

1
3
-2.5+1
2
3
1
8

=[1

1
3
+1
2
3
-2.5]÷
1
8

=[3-2.5]÷

1
8

=0.5÷

1
8

=4.

问答题 简答题
问答题 简答题