问题
解答题
用递等式计算. (1)406+4480÷28 (2)17
(3)
(4)
(5)5-(
(6)[1
|
答案
(1)406+4480÷28,
=406+160,
=566;
(2)17
-15 7
-18 9
,5 7
=17
-15 7
-15 7
,8 9
=16-1
,8 9
=14
;1 9
(3)
÷(3 8
-7 8
)×5.5,1 4
=
÷3 8
×5.5,5 8
=
×5.5,3 5
=3.3;
(4)
÷1 3
+5 4
×2 3
,4 5
=
×1 3
+4 5
×2 3
,4 5
=(
+1 3
)×2 3
,4 5
=1×
,4 5
=
;4 5
(5)5-(
+1 12
)×30,1 15
=5-(
×30+1 12
×30),1 15
=5-(2.5+2),
=5-4.5,
=0.5;
(6)[1
-(2.5-11 3
)]÷2 3
,1 8
=[1
-2.5+11 3
]÷2 3
,1 8
=[1
+11 3
-2.5]÷2 3
,1 8
=[3-2.5]÷
,1 8
=0.5÷
,1 8
=4.