问题
解答题
灵活选择算法脱式计算 (1)
(2)2011×
(3)125×(8+0.8+0.08) (4)
|
答案
(1)
÷(3-1 5
-7 13
)6 13
=
÷[3-(1 5
+7 13
)],6 13
=
÷[3-1],1 5
=
÷2,1 5
=
;1 10
(2)2011×2009 2010
=(2010+1)×
,2009 2010
=2010×
+1×2009 2010
,2009 2010
=2009+
,2009 2010
=2009
;2009 2010
(3)125×(8+0.8+0.08)
=125×8+125×0.8+125×0.08,
=1000+100+10,
=1110;
(4)
÷7 9
+11 5
×5 9 2 11
=
×7 9
+5 11
×5 9
,2 11
=
×5 9
+7 11
×5 9
,2 11
=
×(5 9
+7 11
),2 11
=
×5 9
,9 11
=
.5 11