问题
解答题
(1)2
(2)|2-π|-
(3)(
(4)(
|
答案
(1)原式=2
+22
-22 2
=2
;2
(2)原式=π-2-(π-3)+1
=π-2-π+3+1
=2;
(3)原式=(5
-25
)÷5 5
=3;
(4)原式=3-2+2
=3.
(1)2
(2)|2-π|-
(3)(
(4)(
|
(1)原式=2
+22
-22 2
=2
;2
(2)原式=π-2-(π-3)+1
=π-2-π+3+1
=2;
(3)原式=(5
-25
)÷5 5
=3;
(4)原式=3-2+2
=3.