问题
解答题
计算或化简: (1)(2
(2)
(3)(3
(4)sin230°+cos245°+sin60°•tan45°. |
答案
(1)(2
+3
)(20
-212
),5
=(2
+3
)(4×5
-24×3
),5
=(2
+23
)(25
-23
),5
=(2
)2-(23
)2,5
=12-20,
=-8;
(2)
-9m m 3
-1 m 1 2m
,m3
=3
-m
×m 3
-m m
×m1 2m
,m
=3
-m
-m 3
,m 2
=(3-
-1 3
)1 2
,m
=13 6
;m
(3)(3
-212
+1 3
)÷248
,3
=(3×2
-2×3
+43 3
)÷23
,3
=
÷228 3 3
,3
=
;14 3
(4)sin230°+cos245°+sin60°•tan45°,
=(
)2+(1 2
)2+2 2
×1,3 2
=
+1 4
+1 2
,3 2
=
+3 4
,3 2
=
.3+2 3 4