问题 解答题
计算或化简:
(1)(2
3
+
20
)(
12
-2
5
)

(2)
9m
-
m
3
1
m
-
1
2m
m3

(3)(3
12
-2
1
3
+
48
)÷2
3

(4)sin230°+cos245°+sin60°•tan45°.
答案

(1)(2

3
+
20
)(
12
-2
5
),

=(2

3
+
4×5
)(
4×3
-2
5
),

=(2

3
+2
5
)(2
3
-2
5
),

=(2

3
2-(2
5
2

=12-20,

=-8;

(2)

9m
-
m
3
1
m
-
1
2m
m3

=3

m
-
m
3
×
m
m
-
1
2m
×m
m

=3

m
-
m
3
-
m
2

=(3-

1
3
-
1
2
m

=

13
6
m

(3)(3

12
-2
1
3
+
48
)÷2
3

=(3×2

3
-2×
3
3
+4
3
)÷2
3

=

28
3
3
÷2
3

=

14
3

(4)sin230°+cos245°+sin60°•tan45°,

=(

1
2
2+(
2
2
2+
3
2
×1,

=

1
4
+
1
2
+
3
2

=

3
4
+
3
2

=

3+2
3
4

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