问题 解答题
递等式计算.
(99+
9
10
)÷9       
3
7
÷
7
11
+
4
7
÷
7
11

14
15
÷[(
4
5
+
2
3
)×
10
11
]
5
9
+
5
9
÷
5
3
答案

(1)(99+

9
10
)÷9,

=(99+

9
10
)×
1
9

=99×

1
9
+
9
10
×
1
9

=11+

1
10

=11

1
10

(2)

3
7
÷
7
11
+
4
7
÷
7
11

=

3
7
×
11
7
+
4
7
×
11
7

=(

3
7
+
4
7
)×
11
7

=1×

11
7

=

11
7

(3)

14
15
÷[(
4
5
+
2
3
)×
10
11
],

=

14
15
÷[
22
15
×
10
11
],

=

14
15
÷
20
15

=

7
10

(4)

5
9
+
5
9
÷
5
3

=

5
9
+
3
9

=

8
9

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