问题 解答题
计算:
(1)
1
3
[(2-
3
)
2
+
2
3
+1
];
(2)(
a
-
1
a
+1
)÷
a
-1
a-1

(3)已知x=
3
-
2
3
+
2
,xy=1.求3x2+5xy+3y2的值.
答案

(1)原式=

1
3
(7-4
3
+
3
-1)=2-
3

(2)原式=

a+
a
-1
a
+1
×
(
a
+1)(
a
-1)
a
-1
=a+
a
-1;

(3)∵x=

3
-
2
3
+
2
=(
3
-
2
2=5-2
6
,xy=1,

∴y=5+2

6
,即x+y=10,

∴3x2+5xy+3y2=3(x+y)2-xy=300-1=299.

选择题
单项选择题