问题
解答题
列递等式计算. (1)
(2)56÷
(3)(
(4)14×
(5)1
(6)
|
答案
(1)
-7 8
+3 5
-1 8 2 5
=
+7 8
-(1 8
+3 5
)2 5
=1-1
=0;
(2)56÷
×7 10 5 7
=56×
×10 7 5 7
=
;400 7
(3)(
-11 12
)÷1 6
×1 18 1 3
=
×18×3 4 1 3
=
;9 2
(4)14×
-14 39
÷1414 39
=14×
-14 39
×14 39 1 14
=
×(14-14 39
)1 14
=
×14 39 195 14
=5;
(5)1
÷[321 9
-(32.4-2 5
×0.25)]×121 3
=1
÷[321 9
-(32.4-2 5
)]×121 12
=1
÷[321 9
-32.4+2 5
]×121 12
=
×12×1210 9
=160;
(6)20
-61 2
×1 4 2 5 2+1
÷42 3 1 6
=(20
-61 2
×1 4
)÷(2+12 5
÷42 3
)1 6
=(20
-1 2
×25 4
)÷(2+2 5
×5 3
)6 25
=(20
-21 2
)÷(2+1 2
)2 5
=18×5 12
=
.15 2