问题 解答题
列递等式计算.
(1)
7
8
-
3
5
+
1
8
-
2
5
=
(2)56÷
7
10
×
5
7
=
(3)(
11
12
-
1
6
1
18
×
1
3
=
(4)14×
14
39
-
14
39
÷14
=
(5)1
1
9
÷[32
2
5
-(32.4-
1
3
×0.25)]×12
=
(6)
20
1
2
-6
1
4
×
2
5
2+1
2
3
÷4
1
6
=.
答案

(1)

7
8
-
3
5
+
1
8
-
2
5

=

7
8
+
1
8
-(
3
5
+
2
5

=1-1

=0;

(2)56÷

7
10
×
5
7

=56×

10
7
×
5
7

=

400
7

(3)(

11
12
-
1
6
1
18
×
1
3

=

3
4
×18×
1
3

=

9
2

(4)14×

14
39
-
14
39
÷14

=14×

14
39
-
14
39
×
1
14

=

14
39
×(14-
1
14

=

14
39
×
195
14

=5;

(5)1

1
9
÷[32
2
5
-(32.4-
1
3
×0.25)]×12

=1

1
9
÷[32
2
5
-(32.4-
1
12
)]×12

=1

1
9
÷[32
2
5
-32.4+
1
12
]×12

=

10
9
×12×12

=160;

(6)

20
1
2
-6
1
4
×
2
5
2+1
2
3
÷4
1
6

=(20

1
2
-6
1
4
×
2
5
)÷(2+1
2
3
÷4
1
6

=(20

1
2
-
25
4
×
2
5
)÷(2+
5
3
×
6
25

=(20

1
2
-2
1
2
)÷(2+
2
5

=18×

5
12

=

15
2

单项选择题 A1/A2型题
填空题