问题 解答题
递等式计算
3
4
÷3-
1
10
)×(1-
1
3

3
5
-
3
4
÷3+
3
5

4
9
÷(
5
6
-
1
2
)+
5
16

[2
1
3
-(90%+
2
3
)]÷
7
5

3
4
+0.25÷(
2
3
-1.5×
1
3
答案

(1)(

3
4
÷3-
1
10
)×(1-
1
3
),

=(

1
4
-
1
10
)×(1-
1
3
),

=

3
20
×
2
3

=

1
10

(2)

3
5
-
3
4
÷3+
3
5

=

3
5
-
1
4
+
3
5

=(

3
5
+
3
5
)-
1
4

=

6
5
-
1
4

=

19
20

(3)

4
9
÷(
5
6
-
1
2
)+
5
16

=

4
9
÷
1
3
+
5
16

=

4
3
+
5
16

=

79
48

(4)[2

1
3
-(90%+
2
3
)]÷
7
5

=[2

1
3
-
9
10
-
2
3
7
5

=[2

1
3
-
2
3
-
9
10
7
5

=[

5
3
-
9
10
]÷
7
5

=

23
30
×
5
7

=

23
42

(5)

3
4
+0.25÷(
2
3
-1.5×
1
3
),

=

3
4
+
1
4
÷(
2
3
-
3
2
×
1
3
),

=

3
4
+
1
4
÷(
2
3
-
1
2
),

=

3
4
+
1
4
÷
1
6

=

3
4
+
6
4

=

9
4

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