问题
解答题
递等式计算(能简便的要简便计算) (1)
(2)
(3)
|
答案
(1)
÷(13 16
+7 8
)13 16
=
÷(13 16
+14 16
),13 16
=
÷13 16
,27 16
=
×13 16
,16 27
=
;13 27
(2)
+(7 8
-1 4
)÷1 5 1 4
=
+(7 8
-5 20
)×4,4 20
=
+7 8
×4,1 20
=
+7 8
,1 5
=
+35 40
,8 40
=
;43 40
(3)
×[4 9
-(3 4
-7 16
)]1 4
=
×[4 9
+3 4
-1 4
],7 16
=
×4 9
,9 16
=
.1 4