问题
解答题
(1)计算(
(2)
|
答案
(1)原式=
×3
-26
+3
×2
-26
=32
-22
+23
-23
=2
;2
(2)原式=2ab
•(-2a
a3 2
)÷32b
=2ab•(-ab
a)•3 2 1 3
=-2a2b.2a•2b ab
(1)计算(
(2)
|
(1)原式=
×3
-26
+3
×2
-26
=32
-22
+23
-23
=2
;2
(2)原式=2ab
•(-2a
a3 2
)÷32b
=2ab•(-ab
a)•3 2 1 3
=-2a2b.2a•2b ab