问题 解答题
用递等式计算
36÷[(
2
3
-
2
5
3
5
)]

1÷[(
7
12
-
1
6
)×3]

7
20
×(1-
5
14
÷
5
7
)
答案

36÷[(

2
3
-
2
5
)÷
3
5
]

=36÷[

4
15
×
5
3
],

=36×

9
4

=81;

1÷[(

7
12
-
1
6
)×3]

=1÷[

5
12
×3],

=1×

4
5

=

4
5

7
20
×(1-
5
14
÷
5
7

=

7
20
×(1-
1
2
),

=

7
20
×
1
2

=

7
40

单项选择题
单项选择题