问题 解答题
计算:
(1)解方程:x2+2x-63=0.               
(2)计算:
3tan30°
3cos230°-2sin30°

(3)计算:(10
48
-6
27
+4
12
6
答案

(1)x2+2x-63=0,

分解因式得:(x-7)(x+9)=0,

可得x-7=0或x+9=0,

解得:x1=-9,x2=7;

(2)原式=

3
3
3×(
3
2
)
2
-2×
1
2

=

3
9
4
-1

=

4
3
5

(3)原式=10

48÷6
-6
9
2
+4
12÷6

=20

2
-9
2
+4
2

=15

2

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