问题
解答题
(1)(
(2)(1-
(3)(3.6×
(4)2
|
答案
(1)(
×3.75÷122 5
)+(5 7
+1 3
÷22 3
÷3)2 9
=(
×22 5
×15 4
)+(7 12
+1 3
×2 3
×9 20
)1 3
=9
+(5 8
+1 3
)1 10
=9
+5 8 13 30
=10
;7 120
(2)(1-
+1 2
-1 3
+1 4
)×(1 5
×14 15
÷2 5
)4 15
=(1-
+30 60
-20 60
+15 60
)×(12 60
×4 15
×7 5
)15 4
=
×47 60
×4 15
×7 5 15 4
=1
;29 300
(3)(3.6×
-24÷200)÷11 20
+1 5
×0.211 4
=(3.6×0.05-24÷200)÷1.2+3.75×0.2
=(0.18-0.12)÷1.2+0.75
=0.06÷1.2+0.75
=0.05+0.75
=0.8;
(4)2
+0.039÷[1 2
×(2.31÷0.077)]-0.5261 20
=2.5+0.039÷[0.05×30]-0.526
=2.5+0.039÷1.5-0.526
=2.5+0.026-0.526
=2.