问题
解答题
计算: (1)
(2)(
(3)(3+
(4)2abc
(5)
(6)(
|
答案
(1)
-3
+218 12
=
-33
+42 3
=5
-33
.2
(2)(
-1 2
)×3 3 24
=
-
×241 2
×3 3 24
=2
-23
.2
(3)(3+
)(36
-22
)3
=9
-62
+63
-63 2
=3
.2
(4)2abcc3 2a4b
=2abc•c 2bc 2a2b
=c2 a
.2bc
(5)0.01×81 0.25×144
=0.1×9 0.5×12
=
.3 20
(6)(
-1)2+(2+3
)(2-3
)3
=3+1-2
+4-33
=5-2
.3