问题
解答题
(1)化简
(2)证明等式:
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答案
(1)原式=
=-1;cos10°-sin10° sin10°-cos10°
(2)左边=
=2sin2
+2sinx 2
cosx 2 x 2 2cos 2
+2sinx 2
cosx 2 x 2 sin x 2 cos x 2
右边=
=2sin x 2 2cos 2 x 2
,左边=右边sin x 2 cos x 2
故原式成立.
(1)化简
(2)证明等式:
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(1)原式=
=-1;cos10°-sin10° sin10°-cos10°
(2)左边=
=2sin2
+2sinx 2
cosx 2 x 2 2cos 2
+2sinx 2
cosx 2 x 2 sin x 2 cos x 2
右边=
=2sin x 2 2cos 2 x 2
,左边=右边sin x 2 cos x 2
故原式成立.