问题 解答题
递等式计算.
(1)8×
5
6
+
2
5
÷4(2)(
1
3
-
1
4
)÷
1
2
+
5
6

(3)
5
8
÷(
1
6
+
3
4
×
5
6
)(4)[1-(
3
5
-
3
10
)]÷
7
8
答案

(1)8×

5
6
+
2
5
÷4,

=

20
3
+
1
10

=6

23
30

(2)(

1
3
-
1
4
)÷
1
2
+
5
6

=

1
12
÷
1
2
+
5
6

=

1
6
+
5
6

=1,

(3)

5
8
÷(
1
6
+
3
4
×
5
6
),

=

5
8
÷(
1
6
+
5
8
),

=

5
8
÷
19
24

=

15
19

(4)[1-(

3
5
-
3
10
)]÷
7
8

=(1-

3
10
)÷
7
8

=

7
10
÷
7
8

=

4
5

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