问题 解答题
计算:
(1)
32
-(2+
2
2
(2)
1
2
3
÷
2
1
3
×
1
2
5

(3)
3
3
+(-2)2×
1
8
-
3
+(
2005
-
2004
)0
答案

(1)原式=4

2
-(4+4
2
+2)

=4

2
-4-4
2
-2

=-6;

(2)原式=

5
3
÷
7
3
×
7
5

=

5
3
×
3
7
×
7
5

=1;

(3)原式=

3
+4×
2
4
-
3
+1

=

3
+
2
-
3
+1

=

2
+1.

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