问题 解答题
脱式计算
①9028-(4028+523)-477  
②8
7
8
-[8-(2.125-0.125÷
1
8
)]
③3
1
8
÷[(4
5
12
-3
13
24
)×
4
7
+(3
1
18
-2
7
12
)×1
10
17
]
④(1-
1
2×2
)(1-
1
3×3
)(1-
1
4×4
)…(1-
1
2001×2001
答案

(1)9028-(4028+523)-477

=(9028-4028)-(523+477),

=5000-1000,

=4000;

(2)8

7
8
-[8-(2.125-0.125÷
1
8
)]

=8

7
8
-[8-(2
1
8
-
1
8
÷
1
8
)],

=8

7
8
-[8-(2
1
8
-1)],

=8

7
8
-[8-1
1
8
],

=8

7
8
+1
1
8
-8,

=10-8

=2;

(3)3

1
8
÷[(4
5
12
-3
13
24
)×
4
7
+(3
1
18
-2
7
12
)×1
10
17
]

=

25
8
÷[(
53
12
-
85
24
)×
4
7
+(
55
18
-
31
12
)×
27
17
],

=

25
8
÷[
21
24
×
4
7
+
17
36
×
27
17
],

=

25
8
÷[
1
2
+
3
4
],

=

25
8
×
4
5

=

5
2

(4)(1-

1
2×2
)(1-
1
3×3
)(1-
1
4×4
)…(1-
1
2001×2001

=

1×3
2×2
×
2×4
3×3
×
3×5
4×4
×…×
1999×2001
2000×2000
×
2000×2002
2001×2001

=

1
2
×
2002
2001

=

1001
2001

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