问题
解答题
已知A为锐角,sinA=
|
答案
cos2A=1-2sin2A=1-
×2=9 25 7 25
∵A为锐角,sinA=3 5
∴tanA=
=sinA 1-sin2A 3 4
∴tanB=tan[A-(A-B)]=
=tanA-tan(A-B) 1+tanAtan(A-B)
=2
+3 4 1 2 1-
×3 4 1 2
已知A为锐角,sinA=
|
cos2A=1-2sin2A=1-
×2=9 25 7 25
∵A为锐角,sinA=3 5
∴tanA=
=sinA 1-sin2A 3 4
∴tanB=tan[A-(A-B)]=
=tanA-tan(A-B) 1+tanAtan(A-B)
=2
+3 4 1 2 1-
×3 4 1 2