问题
解答题
计算题: (1)
(2)
(3)(4+
(4)
|
答案
(1)原式=3
+35
-22
+52 5
=8
+5
;2
(2)原式=2
+3x
-2x x
=3
;x
(3)原式=16-5
=11;
(4)原式=
•(-2 b
)•3•3 2 ab•a3b• a b
=-
•9 b a5b
=-9a2 b
.ab
计算题: (1)
(2)
(3)(4+
(4)
|
(1)原式=3
+35
-22
+52 5
=8
+5
;2
(2)原式=2
+3x
-2x x
=3
;x
(3)原式=16-5
=11;
(4)原式=
•(-2 b
)•3•3 2 ab•a3b• a b
=-
•9 b a5b
=-9a2 b
.ab