问题 解答题
计算:
(1)3
2
-2
12
-4
1
8
+3
48

(2)(
3
-1
2-(
1
2
-1+
4
3
+1
+(1-
2
0
(3)
a
b
a2b
×2
b2
a
÷
2
3
a3b

(4)
a2b
+a
b
a
-b
a
b
-
ab2
答案

(1)原式=3

2
-4
3
-
2
+12
3
=2
2
+8
3

(2)原式=3-2

3
+1-2+2(
3
-1)+1=3-2
3
+1-2+2
3
-2+1=1;

(3)原式=

a
b
•2•
3
2
a2b•
b2
a
1
a3b
=
3a
b
b2
a2
=
3a
b
b
a
=3;

(4)原式=a

b
+
ab
-
ab
-b
a
=a
b
-b
a

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