问题
解答题
计算 (1)|-2|-
(2)
(3)(2
(4)
|
答案
(1)原式=2-3+1
=0;
(2)原式=4
+32
-2 2 4
=
;27 2 4
(3)原式=(4
-3
)×3 6
=3
×3 6
=9
;2
(4)原式=
×5 3
×3 7 7 5
=1.
计算 (1)|-2|-
(2)
(3)(2
(4)
|
(1)原式=2-3+1
=0;
(2)原式=4
+32
-2 2 4
=
;27 2 4
(3)原式=(4
-3
)×3 6
=3
×3 6
=9
;2
(4)原式=
×5 3
×3 7 7 5
=1.