问题
解答题
已知sin(π+α)=
|
答案
∵sin(π+α)=
∴sinα=-1 2 1 2
∴sin(π-α)-tan(-α-π)•sin(
+α)π 2
=sinα+tanαcosα=2sinα=-1
搜题请搜索小程序“爱下问搜题”
已知sin(π+α)=
|
∵sin(π+α)=
∴sinα=-1 2 1 2
∴sin(π-α)-tan(-α-π)•sin(
+α)π 2
=sinα+tanαcosα=2sinα=-1