问题
解答题
计算 (1)
(2)(2-
|
答案
(1)原式=6
+33
+43
-42 2
=9
;3
(2)原式=(2-
)2005•(2+5
)2005•(2+5
)5
=[(2-
)•(2+5
)]2005•(2+5
)5
=2+
.5
计算 (1)
(2)(2-
|
(1)原式=6
+33
+43
-42 2
=9
;3
(2)原式=(2-
)2005•(2+5
)2005•(2+5
)5
=[(2-
)•(2+5
)]2005•(2+5
)5
=2+
.5