问题 解答题
已知:|
a
|=2,|
b
|=5,<
a
b
>=60°,求:
a
b

②(2
a
+
b
)•
b

③|2
a
+
b
|;
④2
a
+
b
b
的夹角的余弦值.
答案

∵|

a
|=2,|
b
|=5,<
a
b
>=60°,

∴①

a
b
=|
a
|•|
b
|•cos60°=2×5×
1
2
=5.

②(2

a
+
b
)•
b
=2
a
b
+
b
2
=2×5+52=35.

③|2

a
+
b
|=
(2
a
+
b
)2
=
4
a
2
+4
a
b
+
b
2
=
22+4×5+52
=
61

④cos<2

a
+
b
b
>=
(2
a
+
b
)•
b
|2
a
+
b
|•|
b
|
=
35
61
•5
=
7
61
61

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