问题
填空题
已知
|
答案
∵
=(2,1),a
=(3,λ),b
∴
•a
=6+λ,b
2=9+λ2b
∵(2
-a
)⊥b b
∴(2
-a
)•b
=0b
即2
•a
-b
2=0b
即12+2λ-9-λ2=0
解得λ=3或-1
故答案为:3或-1
已知
|
∵
=(2,1),a
=(3,λ),b
∴
•a
=6+λ,b
2=9+λ2b
∵(2
-a
)⊥b b
∴(2
-a
)•b
=0b
即2
•a
-b
2=0b
即12+2λ-9-λ2=0
解得λ=3或-1
故答案为:3或-1