问题 解答题
递等式计算  
7
9
×
5
11
+
2
9
×
5
11
      
5-5×
2
5
+
3
5

[
1
2
-(
3
4
-
3
5
)]÷
7
10
答案

(1)

7
9
×
5
11
+
2
9
×
5
11

=

5
11
×(
7
9
 +
2
9
),

=

5
11
×1,

=

5
11

(2)5-5×

2
5
+
3
5

=5-2+

3
5

=3

3
5

(3)[

1
2
-(
3
4
-
3
5
)]÷
7
10

=[

1
2
-
3
20
7
10

=

7
20
×
10
7

=

1
2

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