问题 解答题
用合理的方法计算.
(1)8(x-2)=2(x+7)
(2)
2010
2011
×2012
    
(3)(
5
8
+
1
27
)×8+
19
27

(4)
3
5
×(
1
7
+
8
21
+
2
3
)
         
(5)
1
6
×[1÷(
3
5
-
3
10
)]
答案

(1)8(x-2)=2(x+7),

        8x-16=2x+14,

     8x-16-2x=2x+14-2x,

        6x-16=14,

     6x-16+16=14+16,

           6x=30,

        6x÷6=30÷6,

            x=5;

(2)

2010
2011
×2012,

=

2010
2011
×(2011+1),

=

2010
2011
×2011+
2010
2011
×1,

=2010+

2010
2011

=2010

2010
2011

(3)(

5
8
+
1
27
)×8+
19
27

=

5
8
×8+
1
27
×8+
19
27

=5+

8
27
+
19
27

=5+(

8
27
+
19
27
),

=5+1,

=6;

(4)

3
5
×(
1
7
+
8
21
+
2
3
),

=

3
5
×(
11
21
+
2
3
),

=

3
5
×
25
21

=

5
7

(5)

1
6
×[1÷(
3
5
-
3
10
)],

=

1
6
×[1÷
3
10
],

=

1
6
×
10
3

=

5
9

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