问题
选择题
如图所示，电路中，L为一自感线圈，两支路电阻相等，则（ ）
A．闭合开关S时，稳定前电流表A1的示数小于电流表A2的示数
B．闭合开关S时，稳定前电流表A1的示数等于电流表A2的示数
C．闭合开关S时，稳定前电流表A1的示数大于电流表A2的示数
D．断开开关S时，稳定前电流表A1的示数等于电流表A2的示数
答案
CD
分析：电路中有线圈，当通过线圈的电流发生变化时会产生感应电动势去阻碍线圈中电流变化．
解答：解：闭合开关S时，导致线圈中电流增加，则产生反感电动势，从而阻碍电流的增加，所以稳定前电流表A1的示数大于A2的示数．故AB错误C正确；
断开开关S时，导致线圈中电流减小，则产生反感电动势，从而阻碍电流的减小，则线圈与电阻串联构成一个新电路，所以稳定前电流表A1的示数仍等于A2的示数．故D正确；
故选：CD
点评：线圈电流增加，相当于一个瞬间电源接入电路，线圈左端是电源正极．当电流减小时，相当于一个瞬间电源，线圈左端是电源负极．
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