问题 解答题
用递等式计算.
①960÷30-10
5
6
×2÷
30
31
③(
5
9
+
7
6
)×36
④52-2.5×0.9×4
7
8
÷[(
3
4
-
1
2
4
5
]
答案

①960÷30-10,

=32-10,

=22;

5
6
×2÷
30
31

=

5
3
÷
30
31

=

31
18

③(

5
9
+
7
6
)×36,

=

5
9
×36+
7
6
×36,

=20+42,

=62;

④52-2.5×0.9×4,

=52-2.5×4×0.9,

=52-10×0.9,

=52-9,

=43;

7
8
÷[(
3
4
-
1
2
4
5
],

=

7
8
÷[
1
4
÷
4
5
],

=

7
8
÷
5
16

=

14
5

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