问题 解答题
四边形ABCD中,
AB
=(6,1),
BC
=(x,y),
CD
=(-2,-3)

(1)若
BC
DA
,试求x与y满足的关系式;
(2)满足(1)的同时又有
AC
BD
,求x,y的值及四边形ABCD的面积.
答案

BC
=(x,y)
DA
=-
AD
=-(
AB
+
BC
+
CD
)=-(x+4,y-2)=(-x-4,-y+2)

(1)∵

BC
DA

∴x•(-y+2)-y•(-x-4)=0,

化简得:x+2y=0;

(2)

AC
=
AB
+
BC
=(x+6,y+1),

BD
=
BC
+
CD
=(x-2,y-3)

AC
BD

∴(x+6)•(x-2)+(y+1)•(y-3)=0

化简有:x2+y2+4x-2y-15=0,

联立

x+2y=0 
x2+y2+4x-2y-15=0

解得

x=-6
y=3
x=2
y=-1

BC
DA
AC
BD

则四边形ABCD为对角线互相垂直的梯形

x=-6
y=3
AC
=(0,4)   
BD
=(-8,0)

此时SABCD=

1
2
•|
AC
|•|
BD
|=16

x=2
y=-1
AC
=(8,0)   
BD
=(0,-4)

此时SABCD=

1
2
•|
AC
|•|
BD
|=16.

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