问题
解答题
已知tanx=2,求
|
答案
∵tanx=2,
∴
+sin2x=cosx+sinx cosx-sinx
+1+tanx 1-tanx
=sin2x sin2x+cos2x
+1+2 1-2
=-3+tan2x tan2x+1
=-24 4+1 1 5
已知tanx=2,求
|
∵tanx=2,
∴
+sin2x=cosx+sinx cosx-sinx
+1+tanx 1-tanx
=sin2x sin2x+cos2x
+1+2 1-2
=-3+tan2x tan2x+1
=-24 4+1 1 5