问题 解答题
能用简便方法的用简便方法.
(1)
7
10
+(
4
5
-
1
4
)÷2
3
4
                
(2)[
3
5
-(
9
16
-
2
5
)]×1
1
7

(3)20.07×1994-19.93×2007     
(4)54÷[6.3-1
3
4
×(1
2
3
+
19
21
)]

(5)(1+
1
2
+
1
3
+
1
4
)×(
1
2
+
1
3
+
1
4
+
1
5
)-(1+
1
2
+
1
3
+
1
4
+
1
5
)×(
1
2
+
1
3
+
1
4
)
答案

(1)

7
10
+(
4
5
-
1
4
)÷2
3
4

=

7
10
+
11
20
÷2
3
4

=

7
10
+
1
5

=

9
10

(2)[

3
5
-(
9
16
-
2
5
)]×1
1
7

=[

3
5
-
9
16
+
2
5
]×1
1
7

=[

3
5
+
2
5
-
9
16
]×1
1
7

=[1-

9
16
]×1
1
7

=

7
16
×1
1
7

=

1
2

(3)20.07×1994-19.93×2007,

=20.07×1994-1993×20.07,

=20.07×,

=20.07×1,

=20.07;

(4)54÷[6.3-1

3
4
×(1
2
3
+
19
21
)],

=54÷[6.3-1

3
4
×
18
7
],

=54÷[6.3-4.5],

=54÷1.8,

=30;

(5)令

1
2
+
1
3
+
1
4
=a,
1
2
+
1
3
+
1
4
+
1
5
=b;

原式=(1+a)•b-(1+b)•a=b-a;

所以,(1+

1
2
+
1
3
+
1
4
)×(
1
2
+
1
3
+
1
4
+
1
5
)-(1+
1
2
+
1
3
+
1
4
+
1
5
)×(
1
2
+
1
3
+
1
4
)

=(

1
2
+
1
3
+
1
4
+
1
5
)-(
1
2
+
1
3
+
1
4
),

=

1
5

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