问题 解答题
已知平面坐标系中,点O为原点,A(-3,-4),B(5,-12)
(1)若
OC
=
OA
+
OB
OD
=
OA
-
OB
,求
OC
OD
的坐标;
(2)求
OA
OB

(3)若点P在直线AB上,且
OP
AB
,求
OP
的坐标.
答案

(1)∵

OA
=(-3,-4)
OB
=(5,-12)

OC
=
OA
+
OB
=(-3,-4)+(5,-12)=(2,-16)
OD
=
OA
-
OB
=(-3,-4)-(5,-12)=(-8,8)…(3分)

(2)

OA
OB
=(-3)×5+(-4)×(-12)=-15+48=33

(3)设P(m,n)

∵P在AB上,

BA
PA
共线
BA
=(-8,8)
PA
(-3-m,-4-n)

∴(-8)•(-4-n)-8(-3-m)=0

即m+n=-7①又∵

OP
AB
∴(m,n)•(8,-8)=0

那m-n=0②由①②解得m=-

7
2
,n=-
7
2
OP
=(-
7
2
,-
7
2
)

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