问题
解答题
已知平面坐标系中,点O为原点,A(-3,-4),B(5,-12) (1)若
(2)求
(3)若点P在直线AB上,且
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答案
(1)∵
=(-3,-4)OA
=(5,-12)OB
∴
=OC
+OA
=(-3,-4)+(5,-12)=(2,-16)OB
=OD
-OA
=(-3,-4)-(5,-12)=(-8,8)…(3分)OB
(2)
•OA
=(-3)×5+(-4)×(-12)=-15+48=33OB
(3)设P(m,n)
∵P在AB上,
∴
与BA
共线PA
=(-8,8)BA
(-3-m,-4-n)PA
∴(-8)•(-4-n)-8(-3-m)=0
即m+n=-7①又∵
⊥OP
∴(m,n)•(8,-8)=0AB
那m-n=0②由①②解得m=-
,n=-7 2
即7 2
=(-OP
,-7 2
)7 2