问题 解答题
用递等式计算
1
3
4
-0.45+3
11
20
15-4
4
9
+6
5
9
6
5
6
+0.65+
1
6
+
7
20
14
1
6
-(3
7
15
+8
9
20
2
1
3
-0.8+(0.25-
1
15
答案

(1)1

3
4
-0.45+3
11
20

=1.3+3

11
20

=4.85;

(2)15-4

4
9
+6
5
9

=10

5
9
+6
5
9

=17

1
9

(3)6

5
6
+0.65+
1
6
+
7
20

=(6

5
6
+
1
6
)+(0.65+
7
20
),

=7+1,

=8;

(4)14

1
6
-(3
7
15
+8
9
20
),

=14

1
6
-11
11
12

=2

1
4

(5)2

1
3
-0.8+(0.25-
1
15
),

=1

8
15
+
11
60

=1

43
60

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