问题
解答题
已知
(1)
(2)求
|
答案
(1)由条件|
|=|a
|=|b
-a
|,可得 b
2=a
2=b
2+a
2-2b
•a
,∴b
•a
=b
=
2a 2
,∴|
2b 2
+a
|=b
=(
+a
)2b
|3
|.a
∴cos<
,a
+a
>=b
=
•(a
+a
)b |
|•|a
+a
|b
=
2+a
•a b |
|•a
|3
|a
,∴<3 2
,a
+a
>=30°.b
(2)
=|
+a
|2b
•a b
=
2+2a
•a
+b
2b
•a b
=6.3
2a
2a 2