问题
填空题
若(x+3)2+
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答案
∵(x+3)2+
=0,y-2
∴x+3=0,x=-3,
y-2=0,y=2,
∴xy=-3×2=-6,
故答案为:-6.
若(x+3)2+
|
∵(x+3)2+
=0,y-2
∴x+3=0,x=-3,
y-2=0,y=2,
∴xy=-3×2=-6,
故答案为:-6.
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