问题 解答题
用递等式计算,能简算的要简算
4
17
+
1
25
)×17×25
8.1÷〔(4
1
7
-0.005×700)÷1
2
7
+3〕
1234÷1234
1234
1235
9999×2222+3334×3333.
答案

(1)(

4
17
+
1
25
)×17×25,

=(

4
17
+
1
25
)×(17×25),

=(

4
17
×17×25)+(
1
25
×25×17),

=(4×25)+(1×17),

=100+17,

=117;

(2)8.1÷[(4

1
7
-0.005×700)÷1
2
7
+3],

=8.1÷[(4

1
7
-3.5)÷1
2
7
+3],

=8.1÷[

9
14
÷1
2
7
+3],

=8.1÷[

1
2
+3],

=8.1÷3

1
2

=

81
35

(3)1234÷1234

1234
1235

=1234÷

1234×1235+1234
1235

=1234÷

1234×(1235+1)
1235

=1234÷

1234×1236
1235

=1234×

1235
1234×1236

=

1235
1236

(4)9999×2222+3334×3333,

=3333×6666+3334×3333,

=3333×(6666+3334),

=3333×10000,

=33330000.

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