问题
填空题
观察下列各式:(1)
|
答案
∵(1)
=1- 1 2
(2)1 2
=22- 2 5
(3)2 5
=33- 3 10
(4)3 10
=44- 4 17
,…,4 17
∴第(n)个式子为:
=nn- n n2+1
.n n2+1
故答案为:
=nn- n n2+1
.n n2+1
观察下列各式:(1)
|
∵(1)
=1- 1 2
(2)1 2
=22- 2 5
(3)2 5
=33- 3 10
(4)3 10
=44- 4 17
,…,4 17
∴第(n)个式子为:
=nn- n n2+1
.n n2+1
故答案为:
=nn- n n2+1
.n n2+1