问题
解答题
|
答案
①2005×
,2002 2004
=(2004+1)×
,2003 2004
=2004×
+2003 2004
,2003 2004
=2003+
,2003 2004
=2003
;2003 2004
②999
+998 9
+98 9
+8 9
,1 3
=999
+998 9
+98 9
+8 9
,3 9
=(999
+8 9
)+(991 9
+8 9
)+(91 9
+8 9
),1 9
=1000+100+10,
=1110;
③
÷[8 49
-(9 8
+1 8
)],3 7
=
÷[8 49
-9 8
-1 8
],3 7
=
÷[1-8 49
],3 7
=
÷8 49
,4 7
=
×8 49
,7 4
=
;2 7
④1.3-3.79+9.7-6.21,
=(1.3+9.7)-(3.79+6.21),
=11-10,
=1.