问题 解答题
若a,b为实数,且|a-1|+
ab-2
=0,求
1
ab
+
1
(a+1)(b+1)
+
1
(a+2)(b+2)
+…+
1
(a+2009)(b+2009)
的值.
答案

∵|a-1|+

ab-2
=0,

∴a-1=0,ab-2=0,

解得a=1,b=2,

1
ab
+
1
(a+1)(b+1)
+
1
(a+2)(b+2)
+…+
1
(a+2009)(b+2009)

=

1
1×2
+
1
2×3
+…+
1
2010×2011

=1-

1
2
+
1
2
-
1
3
1
2010
-
1
2011

=1-

1
2011

=

2010
2011

判断题
单项选择题