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问题 选择题

某化学反应的微观过程如图所示。下列说法中，不合理的是

A．该反应属于置换反应

B．化学反应前后，原子的种类不变

C．物质丁的化学式是H2O

D．甲、乙两物质参加反应的分子个数比为1:3

答案

答案：A

题目分析：根据图示可知，甲为CO2；乙为氢气H2；丙为CH3OH；根据反应前后原子的种类和数目不变可知：丁为H2O。所以反应的化学方程式为： CO2+3H2一定条件CH3OH+H2O。A．该反应是由“一种单质和一种化合物生成两种化合物的反应”，不属于置换反应。此项不正确。B．化学反应前后，原子的种类不变。此项正确。C．物质丁的化学式是H2O；此项正确。D．甲、乙两物质参加反应的分子个数比为1:3。此项正确。所以应选A项。

填空题



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