问题
解答题
在平面直角坐标系中,已知点A(1,2),B(3,4),C(5,0). 求:(Ⅰ) |
(Ⅱ)
|
答案
(Ⅰ)∵
=(3-1,4-2)=(2,2),AB
=(5-1,0-2)=(4,-2),AC
∴|
|=AB
=22+22
=28
,2
|
|=AC
=42+(-2)2
=220
.5
(Ⅱ) 易知
•AB
=(2,2)•(4,-2)=4,AC
故cos<
,AB
>=cos∠BAC=AC
=
•AB AC |
||AB
|AC
.10 10