问题 解答题
已知|
a
|=4,|
b
|=3,(2
a
-3
b
)•(2
a
+
b
)=61

(1)求
a
b
的值;
(2)求
a
b
的夹角θ;
(3)求|
a
+
b
|
答案

(1)由(2

a
-3
b
)•(2
a
+
b
)=61得
a
b
=
1
4
(4
a
2
-3
b
2
-61)=
1
4
(4×16-3×9-61)=-6

(2)设

a
b
的夹角为θ,则cosθ=
a
b
|
a
||
b
|
=
-6
4×3
=-
1
2

又0°≤θ≤180°∴θ=120°

(3)|

a
+
b
|=
(
a
+
b
)
2
=
a
2
+2
a
b
+
b
2
=
16-12+9
=
13

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