问题
填空题
已知
|
答案
∵|
|=a |
|a
=1=||
|a |
|a
|,b |
|b
?a
=|b
| |a
|cosb
=π 3
|1 2
| |a
|b
∴
2=|(p
+a |
|a
)2=1+1+2?b |
|b
?a |
|a
=2+2×b |
|b
=3,1 2
∴|
|=p
.3
故答案为
.3
已知
|
∵|
|=a |
|a
=1=||
|a |
|a
|,b |
|b
?a
=|b
| |a
|cosb
=π 3
|1 2
| |a
|b
∴
2=|(p
+a |
|a
)2=1+1+2?b |
|b
?a |
|a
=2+2×b |
|b
=3,1 2
∴|
|=p
.3
故答案为
.3