将某灯泡接到电压不变的电源两端，灯泡的电功率为40瓦。如果将灯泡和某电阻R串联后再接到上述电源的两端，电阻的电功率为3.6瓦，不考虑灯泡的电阻随温度而发生变化，且灯泡的电阻小于R，则此时灯泡的电功率为： [ ]

A．14.4瓦

B．32.4瓦

C．0.4瓦

D．0.9瓦

In writing up the log book at the end of your watch , you make an error .which of the following is the way to correct the error?（）.

A.Carefully and neatly erase the entryand rewrite it correctly

B.Remove this page of the log book and rewrite all entries on a clean page

C.Blot out the error completely and rewrite the entry correctly

D.Cross out the error with a single line and rewrite the entry correctly