问题 单项选择题

在一台Cisco路由器上,只允许IP地址为212.78.4.100/24的主机和202.34.76.64/26子网上的所有主机远程登录路由器,下列正确的access-list配置是()

A.Router(config) # access-list 30 permit 202.34.76.64 0.0.0.63
Router(config) # access-list 30 permit 212.78.4.100
Router(config) # access-list 30 deny any
Router(config) # line vty 0 5
Router(config-line) # access-class 30 in

B.Router(config) # access-list 30 permit 202.34.76.64 0.0.0.192
Router(config) # access-list 30 permit 212.78.4.100
Router(config) # access-list 30 deny any
Router(config) # line vty 0 5
Router(config-line) # access-class 30 in

C.Router(config) # access-list 30 deny any
Router(config) # access-list 30 permit 202.34.76.64 0.0.0.63
Router(config) # access-list 30 permit 212.78.4.100
Router(config) # line vty 0 5
Router(config-line) # access-class 30 in

D.Router(config) # access-list 30 permit 202.34.76.64 255.255.255.192
Router(config) # access-list 30 permit 212.78.4.100
Router(config) # access-list 30 deny any
Router(config) # line vty 0 5
Router(config-line) # access-class 30 in

答案

参考答案:A

解析:

由202.34.76.64/26的字网掩码255.255.255.192可以算出反码为0.0.0.63.再由定义格式可知A正确。

单项选择题
单项选择题