问题
解答题
已知2a-1的算术平方根是3,3a+b-1的立方根是2,求a+2b的值.
答案
∵2a-1的算术平方根是3,
∴2a-1=9,
∴a=5,
∵3a+b-1的立方根是2,
∴3a+b-1=8,
∴3×5+b-1=8,
∴b=-6,
∴a+2b=5+2×(-6)=5-12=-7.
已知2a-1的算术平方根是3,3a+b-1的立方根是2,求a+2b的值.
∵2a-1的算术平方根是3,
∴2a-1=9,
∴a=5,
∵3a+b-1的立方根是2,
∴3a+b-1=8,
∴3×5+b-1=8,
∴b=-6,
∴a+2b=5+2×(-6)=5-12=-7.
用方框中所给词的适当形式填空。 | |
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