问题
解答题
已知2a-1的算术平方根是3，3a+b-1的立方根是2，求a+2b的值．
答案
∵2a-1的算术平方根是3，
∴2a-1=9，
∴a=5，
∵3a+b-1的立方根是2，
∴3a+b-1=8，
∴3×5+b-1=8，
∴b=-6，
∴a+2b=5+2×（-6）=5-12=-7．
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已知2a-1的算术平方根是3，3a+b-1的立方根是2，求a+2b的值．
∵2a-1的算术平方根是3，
∴2a-1=9，
∴a=5，
∵3a+b-1的立方根是2，
∴3a+b-1=8，
∴3×5+b-1=8，
∴b=-6，
∴a+2b=5+2×（-6）=5-12=-7．
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