问题
填空题
|
答案
定积分∫
0π 2
dxcos2x cosx+sinx
=∫
0π 2
dxcos2x-sin2x cosx+sinx
=
(cosx-sinx)dx∫
0π 2
=（sinx+cosx）|0
=1-1=0．π 2
故答案为：0．
搜题请搜索小程序“爱下问搜题”
|
定积分∫
0π 2
dxcos2x cosx+sinx
=∫
0π 2
dxcos2x-sin2x cosx+sinx
=
(cosx-sinx)dx∫
0π 2
=（sinx+cosx）|0
=1-1=0．π 2
故答案为：0．
